Question Details

(solution) Plot a standard curve using the results of the assay on a range


Plot a standard curve using the results of the assay on a range of nitrite standards and use it to calculate the amount of nitrite produced by the plant tissue. (Make sure that the line of best fit goes through (0, 0)


Knowing the concentration of nitrite in the reaction solution, the volume of solution, the time of incubation and the weight of tissue, express the results obtained as:

µmoles nitrite produced hr-1 g-1fresh weight.

To do this you will need to:

  • Multiply your ?µM NaNO2? figures that you have read off your standard graph for each sample by the volume of the reaction solution volume in litres, i.e. 0.005 litres. (Because molarity figures are effectively amount of chemical per litre.)
  • Divide this µmoles nitrite figure by the length of time incubated in hours and then divide this by the weight of plant tissue used in each case.

Calculate the mean figures and SE for each treatment / plant part and plot a suitable graph to display these figures. HELP!!!!


Chart Title

 

0.8 f(x) = 0.0144181818x 0.7 0.6 0.5 Absorbance at 540nm 0.4 0.3 0.2 0.1 0 0 10 20 30 NaNO2 Concentration (uM) 40 50 60 Fresh Weights (g)

 

Tissue

 

Root

 

Root

 

Root

 

Root

 

Root

 

Root

 

Root

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot Absorbance at 540nm Sample No. Distilled H20

 

1 0.4737

 

2 0.502

 

3 0.541

 

4 0.501

 

5 0.4955

 

6 0.5016

 

7 0.4865

 

1 0.5166

 

2 0.502

 

3 0.502

 

4 0.5072

 

5 0.455

 

6 0.4809

 

7 0.4912 (NH4)2SO4

 

0.5018

 

0.5063

 

0.5646

 

0.5602

 

0.5022

 

0.5715

 

0.5111

 

0.5045

 

0.5051

 

0.5765

 

0.508

 

0.5052

 

0.5315

 

0.5394 uM nitrite produced hr-1g fresh weight-1

 

Tissue

 

Sample No. Distilled H20

 

Root

 

Root

 

Root 1

 

2

 

3 Root

 

Root

 

Root

 

Root

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot KNO3

 

0.5034

 

0.503

 

0.5132

 

0.515

 

0.5076

 

0.5173

 

0.5005

 

0.5313

 

0.4713

 

0.506

 

0.499

 

0.5104

 

0.5307

 

0.5026 (NH4)2SO4 Tissue

 

Root

 

Root

 

Root

 

Root

 

Root

 

Root

 

Root

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot Sample No. Distilled H20

 

1

 

2

 

3

 

4

 

5

 

6

 

7

 

1

 

2

 

3

 

4

 

5

 

6

 

7 KNO3 0.8063 0.11

 

0.05

 

0.309

 

0.062

 

0.018

 

0.001

 

0.167

 

0.107

 

0.061

 

0.106

 

0.059

 

0.015

 

0.009

 

0.076 KNO3

 

0.022

 

0.022

 

0.014

 

0.033

 

0.046

 

0.029 0.604

 

0.321

 

0.155

 

0.043

 

0.237

 

0.784

 

0.953

 

0.038

 

0.099

 

0.149

 

0.08

 

0.105

 

0.112

 

1.204 0.05

 

0.022

 

0.016

 

0.095

 

0.016

 

0.09 Distilled H20 10

 

0.097 20

 

0.236 30

 

0.435 40

 

0.599 50

 

0.732 (NH4)2SO4 Tissue

 

Root

 

Root

 

Root

 

Root

 

Root

 

Root

 

Root

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shoot

 

Shhot (NH4)2SO4

 

Sample No. Distilled H20

 

1

 

7.6389

 

2

 

3

 

4

 

5

 

6

 

7

 

1

 

2

 

3

 

4

 

5

 

6 Standards

 

KNO3 Root

 

Shoot

 

Standard error

 

Tissue

 

Root

 

Shoot 0

 

0 (NH4)2SO4 Mean umoles nitrite produced hr-1g fresh weight-1

 

Distilled H20

 

(NH4)2SO4

 

Tissue 4

 

5

 

6

 

7

 

1

 

2

 

3

 

4

 

5

 

6

 

7 NO2 Standards

 

Conc (uM)

 

Abs at 540nm Nitite produced uM KNO3 Nitrite (uM)

 

0

 

5

 

10

 

20

 

30

 

50 Absorbance KNO3

 


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